JEE Chemistry - MCQ Practice Questions
Practice free JEE Chemistry multiple-choice questions with detailed answers and explanations. Perfect for competitive exam preparation.
457 questions | 100% Free
What is the pH of a buffer solution containing 0.1 M acetic acid and 0.15 M sodium acetate? (Ka = 1.8 × 10⁻⁵)
Ksp of AgCl is 1.8 × 10⁻¹⁰. What is the molar solubility in 0.1 M NaCl solution?
Which of the following has maximum boiling point?
For electrodeposition of copper using 1 Faraday of charge, how many moles of Cu are deposited? Cu²⁺ + 2e⁻ → Cu
At 25°C, for a cell with E°cell = 0.92 V, what is ΔG°? (F = 96485 C/mol)
Which pair of substances will form an ideal solution?
For a reversible adiabatic process, which statement is true?
The rate law for reaction is: rate = k[A]²[B]. If [A] is doubled and [B] is halved, how does rate change?
Which statement correctly defines chemical potential?
For an exothermic reaction at 298 K, which condition favors spontaneity?
The molar conductivity of a weak electrolyte increases with dilution because:
At 1000 K, for the reaction N₂ + O₂ ⇌ 2NO, Kc = 0.025. What is Kp? (R = 0.0831 L·bar/mol·K)
Which of the following best explains why diamond is harder than graphite?
For the reaction 2A(g) ⇌ B(g) + C(g), if initial pressure is 2 atm and degree of dissociation is 0.5, what is the total pressure at equilibrium?
Which of the following factors does NOT affect the value of the equilibrium constant Kc?
A solution contains 0.1 M weak acid HA (Ka = 1×10⁻⁵). The degree of ionization is approximately:
At 298 K, ΔG° for a reaction is -20 kJ/mol. The reaction quotient Q = 0.01 when Kp = 1000. Which statement is true?
The molar heat capacity at constant pressure (Cp) for an ideal gas is 29 J/(mol·K). Its molar heat capacity at constant volume (Cv) is approximately:
For the cell: Zn | Zn²⁺ (0.01 M) || Cu²⁺ (1 M) | Cu, E°cell = 1.1 V at 25°C. The cell potential (Ecell) is:
In a first-order reaction, if the half-life is 10 minutes, the time taken for the concentration to reduce to th of initial value is: