JEE Physics - MCQ Practice Questions
Practice free JEE Physics multiple-choice questions with detailed answers and explanations. Perfect for competitive exam preparation.
900 questions | 100% Free
A force of 10 N acts on a mass for 5 seconds, changing its momentum by:
A disc of radius 0.5 m rolls without slipping on a horizontal surface with angular velocity 4 rad/s. The velocity of the center of mass is:
A man of mass 60 kg stands on a weighing scale in an elevator moving downward with acceleration 2 m/s². The scale reading is (g = 10 m/s²):
A rotating wheel has moment of inertia 2 kg·m² and angular acceleration 3 rad/s². The torque required is:
A particle experiences a force F = 2i + 3j (N) and displacement s = 4i + 6j (m). The work done is:
A uniform rod of mass M and length L is pivoted at one end. The moment of inertia about the pivot is:
A body is projected vertically upward with velocity 40 m/s. If g = 10 m/s², what is the maximum height reached?
A block of mass 5 kg is placed on a frictionless inclined plane at 30°. What is the acceleration down the plane? (g = 10 m/s²)
A particle moves with constant velocity v = 5 m/s in a circular path of radius 10 m. What is its centripetal acceleration?
What is the moment of inertia of a uniform disc of mass M and radius R about an axis perpendicular to the disc passing through its center?
A block slides down a frictionless incline of height 5 m. What is its speed at the bottom? (g = 10 m/s²)
A particle experiences three forces: F₁ = 3i N, F₂ = 4j N, and F₃ = -3i - 4j N. What is the net force magnitude?
A particle undergoes SHM with amplitude A = 0.5 m and angular frequency ω = 4 rad/s. What is its maximum velocity?
A projectile is launched at an angle of 45° with initial velocity 20 m/s. Neglecting air resistance, what is the maximum height reached? (g = 10 m/s²)
A body of mass 2 kg moves in a circular path of radius 0.5 m with constant speed. If the centripetal acceleration is 8 m/s², what is the centripetal force required?
An elevator accelerates upward at 2 m/s². A person of mass 60 kg stands in it. What is the normal force exerted by the floor on the person? (g = 10 m/s²)