JEE Physics - MCQ Practice Questions
Practice free JEE Physics multiple-choice questions with detailed answers and explanations. Perfect for competitive exam preparation.
900 questions | 100% Free
Three identical charges q are placed at the vertices of an equilateral triangle of side a. The electric potential at the centroid is:
A uniformly charged infinite plane sheet has surface charge density σ. The electric field due to the sheet is:
Two concentric spheres have radii r₁ (inner) and r₂ (outer). The inner sphere has charge +Q and outer sphere has charge -Q. The electric field in the region r₁ < r < r₂ is:
A parallel plate capacitor is charged to voltage V and then isolated. If the plate separation is doubled, the energy stored becomes:
A charged particle moves from point A to point B in electrostatic field. The work done by electrostatic force is independent of path because:
A conducting sphere of radius R₁ inside a conducting spherical shell of radius R₂ (R₁ < R₂) has charge Q. The electric field for r > R₂ is:
The capacitance of a spherical conductor of radius R is:
The potential energy of electric dipole in uniform field E is:
Two point charges +8μC and -2μC are separated by 3 m. The electric potential is zero at a point on the line joining them, located at distance x from the +8μC charge. Find x:
A parallel plate capacitor with plate separation d and area A is charged to voltage V. A dielectric of dielectric constant K is inserted between the plates. The change in stored energy is:
Two conducting spheres of radii r₁ and r₂ (r₁ > r₂) have charges Q₁ and Q₂. They are connected by a wire. The final charge distribution will be such that:
The electric field on the axis of a uniformly charged ring of radius a and total charge Q at distance x from the center is:
Two identical metal spheres with charges +Q and -3Q are brought into contact and then separated by distance r. The electrostatic force between them is:
The electric field intensity at distance r from a line charge with linear charge density λ is given by:
A parallel plate capacitor has capacitance C and is charged to voltage V. If voltage is doubled and a dielectric K is inserted, the energy stored becomes:
A metallic sphere of radius R is charged such that surface charge density is σ. If the sphere is surrounded by a dielectric medium of dielectric constant K, how does the electric field just outside the surface change?
Two fixed point charges Q₁ = +2μC and Q₂ = -2μC are separated by 2 m. A test charge +1μC is moved along the perpendicular bisector. At what distance from the midpoint (on the bisector) is the electric field maximum?
A parallel plate capacitor is filled with two dielectrics of thickness d/2 each and dielectric constants K₁ and K₂. What is the equivalent capacitance if the original capacitance (empty) was C₀?
A hollow conducting sphere of radius R carries charge Q. A point charge q is placed at the center. What is the electric field at distance r from center (r > R)?
The electric field just outside a conductor surface is perpendicular to the surface. This is because: