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JEE Chemistry - MCQ Practice Questions

Practice free JEE Chemistry multiple-choice questions with detailed answers and explanations. Perfect for competitive exam preparation.

457 questions | 100% Free

Q.161Hard

Which of the following compounds will show optical isomerism?

Q.162Hard

The decarboxylation of malonic acid derivatives proceeds through:

Q.163Hard

In the crossed Cannizzaro reaction, the aldehyde that acts as both reducing and oxidizing agent is:

Q.164Hard

The rearrangement that occurs during the dehydration of 3-methylbutan-2-ol under acidic conditions is:

Q.165Hard

The mechanism of the esterification reaction between a carboxylic acid and alcohol is:

Q.166Hard

When propyne undergoes hydration in the presence of Hg2+/H2SO4, the major product is:

Q.167Hard

In the reduction of ketones and aldehydes using DIBAL-H, the product is:

Q.168Hard

The directing effect of the amino group (-NH2) in electrophilic aromatic substitution is:

Q.169Hard

In the Robinson annulation reaction, the product formed is:

Q.170Hard

The enolate ion formed from a ketone in basic conditions attacks an alkyl halide in the:

Q.171Easy

Which of the following compounds undergoes SN1 reaction most readily?

Q.172Medium

In the Friedel-Crafts alkylation of benzene with 1-chloropropane and AlCl3, the major product is isopropylbenzene due to:

Q.173Easy

Which reagent is used to differentiate between aldehydes and ketones?

Q.174Medium

The pKa of phenol (C6H5OH) is approximately 10, while that of aliphatic alcohol is around 16. This difference is due to:

Q.175Medium

Which of the following compounds will not give a positive Iodoform test?

Q.176Hard

In the bromination of toluene, the ortho:para ratio is approximately 2:1 instead of 1:1 due to:

Q.177Easy

The oxidation of primary alcohols with chromic acid (H2CrO4) in acidic medium gives:

Q.178Easy

Which mechanism best describes the addition of HBr to propene?

Q.179Medium

In the nitration of anisole (C6H5-O-CH3), the major product is:

Q.180Medium

The reaction of acetyl chloride with aniline preferentially gives N-acetylaniline rather than p-acetylaniline because: