Quantitative Aptitude — MCQ Practice Questions & Answers

Question 1

A train travels 240 km in 4 hours. If it increases its speed by 20%, how much distance will it cover in 5 hours at the new speed?

Accepted Answer

Correct answer: B. 360 km — Step 1: Calculate the original speed The train travels 240 km in 4 hours, so we divide distance by time. 	ext{Original Speed} = \frac{240 	ext{ km}}{4 	ext{ hours}} = 60 	ext{ km/h} Step 2: Calculate the new speed after 20% increase The speed increases by 20%, so we multiply the original speed by 1.20. 	ext{New Speed} = 60 	imes 1.20 = 72 	ext{ km/h} Step 3: Calculate distance covered in 5 hours at new speed Distance equals speed multiplied by time. 	ext{Distance} = 72 	ext{ km/h} 	imes 5 	ext{ hours} = 360 	ext{ km} **The train will cover 360 km in 5 hours at the new speed.**

Answer

A. 300 km

Answer

C. 330 km

Answer

D. 288 km

Question 2

A shopkeeper buys notebooks at ₹40 each and sells them at ₹50 each. If he sells 120 notebooks in a day, what is his total profit?

Accepted Answer

Correct answer: A. ₹1,200 — Step 1: Calculate Total Cost Price The shopkeeper buys 120 notebooks at ₹40 each. 	ext{Total Cost Price} = 120 	imes 40 = ₹4,800 Step 2: Calculate Total Selling Price The shopkeeper sells 120 notebooks at ₹50 each. 	ext{Total Selling Price} = 120 	imes 50 = ₹6,000 Step 3: Calculate Total Profit Profit is the difference between selling price and cost price. 	ext{Total Profit} = 	ext{Selling Price} - 	ext{Cost Price} = 6,000 - 4,800 = ₹1,200 **The shopkeeper's total profit for selling 120 notebooks in a day is ₹1,200.**

Answer

B. ₹1,500

Answer

C. ₹1,800

Answer

D. ₹2,000

Question 3

A sum of money becomes ₹9,600 after 5 years at a simple interest rate of 8% per annum. What was the principal amount?

Accepted Answer

Correct answer: A. ₹6,000 — Step 1: Identify the Simple Interest Formula The formula for amount in simple interest is A = P + SI, where SI = PRT/100 A = P + \frac{PRT}{100} Step 2: Substitute Known Values Given: A = ₹9,600, T = 5 years, R = 8% per annum 9,600 = P + \frac{P 	imes 8 	imes 5}{100} Step 3: Simplify and Solve for Principal 9,600 = P + \frac{40P}{100} 9,600 = P + 0.4P 9,600 = 1.4P P = \frac{9,600}{1.4} = \frac{96,000}{14} = 6,000 **The principal amount was ₹6,000.**

Answer

B. ₹6,857

Answer

C. ₹7,200

Answer

D. ₹8,000

Question 4

A person invests ₹5,000 at 6% per annum simple interest. After how many years will the amount become ₹6,500?

Accepted Answer

Correct answer: C. 5 years — Step 1: Identify the given values Principal (P) = ₹5,000, Rate (R) = 6% per annum, Final Amount (A) = ₹6,500 P = 5000, \quad R = 6\%, \quad A = 6500 Step 2: Calculate the Simple Interest Simple Interest (SI) = Final Amount - Principal SI = A - P = 6500 - 5000 = 1500 Step 3: Apply the Simple Interest formula to find Time Using the formula: SI = \frac{P 	imes R 	imes T}{100} 1500 = \frac{5000 	imes 6 	imes T}{100} 1500 = \frac{30000 	imes T}{100} 1500 = 300 	imes T T = \frac{1500}{300} = 5 	ext{ years} **The amount will become ₹6,500 after 5 years.**

Answer

A. 3 years

Answer

B. 4 years

Answer

D. 6 years

Question 5

A trader buys mangoes at ₹8 per kg and sells them at ₹12 per kg. What is his profit percentage?

Accepted Answer

Correct answer: B. 50% — Step 1: Identify Cost Price and Selling Price Cost Price (CP) = ₹8 per kg and Selling Price (SP) = ₹12 per kg 	ext{CP} = ₹8, \quad 	ext{SP} = ₹12 Step 2: Calculate Profit Profit = Selling Price − Cost Price 	ext{Profit} = ₹12 - ₹8 = ₹4 Step 3: Calculate Profit Percentage Profit percentage is calculated as profit divided by cost price, multiplied by 100 	ext{Profit\%} = \frac{	ext{Profit}}{	ext{Cost Price}} 	imes 100 = \frac{4}{8} 	imes 100 = \frac{1}{2} 	imes 100 = 50\% **The trader's profit percentage is 50%.**

Answer

A. 40%

Answer

C. 60%

Answer

D. 45%

Question 6

If an article is purchased for ₹450 and sold at a loss of 8%, what is the selling price?

Accepted Answer

Correct answer: A. ₹414 — Step 1: Identify the given information Cost Price (CP) = ₹450 and Loss = 8% 	ext{Given: CP} = ₹450, 	ext{ Loss} = 8\% Step 2: Calculate the loss amount Loss amount = 8% of Cost Price 	ext{Loss amount} = \frac{8}{100} 	imes 450 = 0.08 	imes 450 = ₹36 Step 3: Calculate the selling price Selling Price = Cost Price − Loss amount 	ext{SP} = 450 - 36 = ₹414 **The selling price of the article is ₹414.**

Answer

B. ₹418

Answer

C. ₹420

Answer

D. ₹422

Question 7

A retailer buys notebooks at ₹40 each and sells them at ₹50 each. How many notebooks must he sell to make a profit of ₹600?

Accepted Answer

Correct answer: B. 60 — Step 1: Find profit per notebook The retailer buys at ₹40 and sells at ₹50, so profit on each notebook is the difference. 	ext{Profit per notebook} = 50 - 40 = ₹10 Step 2: Set up equation for total profit Let the number of notebooks sold be x. The total profit equals profit per notebook multiplied by number of notebooks. 	ext{Total Profit} = 	ext{Profit per notebook} 	imes 	ext{Number of notebooks} 600 = 10 	imes x Step 3: Solve for number of notebooks Divide both sides by 10 to find x. x = \frac{600}{10} = 60 **The retailer must sell 60 notebooks to make a profit of ₹600.**

Answer

A. 55

Answer

C. 65

Answer

D. 70

Question 8

Rajesh invested ₹5,000 at a simple interest rate of 8% per annum for 3 years. How much total amount will he receive after 3 years?

Accepted Answer

Correct answer: A. ₹6,200 — Step 1: Use SI formula: SI = (P × R × T) / 100. Step 2: SI = (5000 × 8 × 3) / 100 = 120000 / 100 = ₹1,200. Step 3: Total Amount = Principal + SI = 5000 + 1200 = ₹6,200. So option A is correct.

Answer

B. ₹6,400

Answer

C. ₹6,100

Answer

D. ₹6,300

Quantitative Aptitude - MCQ Practice Questions