Quantitative Aptitude — MCQ Practice Questions & Answers

Question 1

A man walks from point A to point B at 4 km/h and returns from B to A at 6 km/h. If the total journey takes 5 hours, what is the distance between A and B?

Accepted Answer

Correct answer: B. 12 km — Step 1: Define Variables and Set Up Equations Let the distance between A and B be d km. Time to go from A to B at 4 km/h is \frac{d}{4} hours, and time to return from B to A at 6 km/h is \frac{d}{6} hours. 	ext{Total time} = \frac{d}{4} + \frac{d}{6} = 5 Step 2: Find Common Denominator and Simplify The common denominator of 4 and 6 is 12. Rewrite each fraction with denominator 12. \frac{3d}{12} + \frac{2d}{12} = 5 Step 3: Solve for Distance Combine the fractions on the left side and solve for d . \frac{5d}{12} = 5 5d = 5 	imes 12 5d = 60 d = 12 	ext{ km} **The distance between A and B is 12 km.**

Answer

A. 10 km

Answer

C. 11 km

Answer

D. 15 km

Question 2

A boat takes 6 hours to travel 120 km downstream and 8 hours to travel the same distance upstream. What is the speed of the boat in still water?

Accepted Answer

Correct answer: A. 17.5 km/h — Step 1: Find the downstream speed The boat travels 120 km downstream in 6 hours. 	ext{Downstream speed} = \frac{120}{6} = 20 	ext{ km/h} Step 2: Find the upstream speed The boat travels 120 km upstream in 8 hours. 	ext{Upstream speed} = \frac{120}{8} = 15 	ext{ km/h} Step 3: Calculate the speed of boat in still water The speed of boat in still water is the average of downstream and upstream speeds. 	ext{Speed of boat} = \frac{	ext{Downstream speed} + 	ext{Upstream speed}}{2} = \frac{20 + 15}{2} = \frac{35}{2} = 17.5 	ext{ km/h} **The speed of the boat in still water is 17.5 km/h.**

Answer

B. 15 km/h

Answer

C. 16 km/h

Answer

D. 18 km/h

Question 3

A trader bought a watch for ₹800. He marked it at 60% above the cost price but offered a discount of 20% on the marked price. What is his profit percentage?

Accepted Answer

Correct answer: A. 28% — Step 1: Calculate the Marked Price The marked price is 60% above the cost price of ₹800. 	ext{Marked Price} = 800 + (60\% 	imes 800) = 800 + 0.60 	imes 800 = 800 + 480 = ₹1280 Step 2: Calculate the Selling Price A discount of 20% is offered on the marked price of ₹1280. 	ext{Selling Price} = 1280 - (20\% 	imes 1280) = 1280 - 0.20 	imes 1280 = 1280 - 256 = ₹1024 Step 3: Calculate the Profit Percentage The profit is the difference between selling price and cost price, divided by cost price and multiplied by 100. 	ext{Profit} = 1024 - 800 = ₹224 	ext{Profit Percentage} = \frac{	ext{Profit}}{	ext{Cost Price}} 	imes 100 = \frac{224}{800} 	imes 100 = 0.28 	imes 100 = 28\% **The trader made a profit of 28% on the watch.**

Answer

B. 32%

Answer

C. 36%

Answer

D. 40%

Question 4

Two articles were sold for ₹1,000 each. One was sold at a profit of 25% and the other at a loss of 25%. What is the overall profit or loss percentage?

Accepted Answer

Correct answer: A. 6.25% loss — Step 1: Find the Cost Price of the article sold at 25% profit [Let CP₁ be the cost price of first article. Selling price = ₹1,000 at 25% profit] SP_1 = CP_1 + 0.25 	imes CP_1 = 1.25 	imes CP_1 = 1000 CP_1 = \frac{1000}{1.25} = \frac{1000 	imes 100}{125} = \frac{100000}{125} = 800 Step 2: Find the Cost Price of the article sold at 25% loss [Let CP₂ be the cost price of second article. Selling price = ₹1,000 at 25% loss] SP_2 = CP_2 - 0.25 	imes CP_2 = 0.75 	imes CP_2 = 1000 CP_2 = \frac{1000}{0.75} = \frac{1000 	imes 100}{75} = \frac{100000}{75} = \frac{4000}{3} \approx 1333.33 Step 3: Calculate overall profit or loss percentage [Total Cost Price and Total Selling Price] 	ext{Total CP} = CP_1 + CP_2 = 800 + \frac{4000}{3} = \frac{2400 + 4000}{3} = \frac{6400}{3} 	ext{Total SP} = 1000 + 1000 = 2000 	ext{Loss} = \

Answer

B. 6.25% profit

Answer

C. No profit, no loss

Answer

D. 5% loss

Question 5

A merchant bought goods for ₹15,000. He spent ₹2,000 on transportation and ₹500 on packaging. If he wants to make a profit of 20%, at what price should he sell the goods?

Accepted Answer

Correct answer: C. ₹21,600 — Step 1: Calculate Total Cost Price The merchant's total cost includes the purchase price, transportation, and packaging costs. 	ext{Total Cost Price} = 15,000 + 2,000 + 500 = 17,500 	ext{ ₹} Step 2: Calculate Profit Amount The merchant wants to make a 20% profit on the total cost price. 	ext{Profit} = 20\% 	ext{ of } 17,500 = \frac{20}{100} 	imes 17,500 = 3,500 	ext{ ₹} Step 3: Calculate Selling Price The selling price is the total cost price plus the profit amount. 	ext{Selling Price} = 17,500 + 3,500 = 21,000 	ext{ ₹} **The merchant should sell the goods at ₹21,000 to make a 20% profit.**

Answer

A. ₹20,400

Answer

B. ₹21,000

Answer

D. ₹22,200

Question 6

The simple interest on a certain sum for 3 years at 12% per annum is ₹3,600. If the same sum is invested for 5 years at 10% per annum, what will be the simple interest earned?

Accepted Answer

Correct answer: B. ₹5,000 — Step 1: Find the Principal using Simple Interest Formula Using the formula SI = PRT/100, where SI = ₹3,600, R = 12% p.a., T = 3 years 3,600 = \frac{P 	imes 12 	imes 3}{100} Step 2: Solve for Principal 3,600 = \frac{36P}{100} P = \frac{3,600 	imes 100}{36} = \frac{360,000}{36} = ₹10,000 Step 3: Calculate Simple Interest for New Investment For P = ₹10,000, R = 10% p.a., T = 5 years SI = \frac{P 	imes R 	imes T}{100} = \frac{10,000 	imes 10 	imes 5}{100} SI = \frac{500,000}{100} = ₹5,000 **The simple interest earned on ₹10,000 invested for 5 years at 10% per annum is ₹5,000.**

Answer

A. ₹4,000

Answer

C. ₹6,000

Answer

D. ₹7,200

Question 7

A sum becomes 4 times itself in 15 years at simple interest. What is the rate of interest per annum?

Accepted Answer

Correct answer: C. 20% — Step 1: Identify the Simple Interest Formula Let Principal = P, Amount = A, Rate = R% per annum, Time = T years A = P + SI 	ext{ where } SI = \frac{P 	imes R 	imes T}{100} Step 2: Set up the equation using given information Given that the sum becomes 4 times itself, so Amount = 4P 4P = P + SI SI = 4P - P = 3P Step 3: Substitute into Simple Interest formula and solve for rate 3P = \frac{P 	imes R 	imes 15}{100} 3P = \frac{15PR}{100} 3 = \frac{15R}{100} R = \frac{3 	imes 100}{15} = \frac{300}{15} = 20\% **The rate of interest per annum is 20%.**

Answer

A. 15%

Answer

B. 18%

Answer

D. 25%

Question 8

A shopkeeper marks an article at ₹500 and gives a discount of 20%. If he still makes a profit of 25%, what was the cost price?

Accepted Answer

Correct answer: B. ₹320 — Step 1: Calculate the Selling Price after discount The marked price is ₹500 and discount is 20%. 	ext{Selling Price} = 500 - (20\% 	ext{ of } 500) = 500 - \frac{20}{100} 	imes 500 = 500 - 100 = ₹400 Step 2: Use the profit formula to find Cost Price The shopkeeper makes a profit of 25%, which means Selling Price is 125% of Cost Price. 	ext{Selling Price} = 	ext{Cost Price} 	imes \left(1 + \frac{	ext{Profit\%}}{100}ight) 400 = 	ext{Cost Price} 	imes \left(1 + \frac{25}{100}ight) 400 = 	ext{Cost Price} 	imes 1.25 Step 3: Solve for Cost Price 	ext{Cost Price} = \frac{400}{1.25} = \frac{400}{\frac{5}{4}} = 400 	imes \frac{4}{5} = \frac{1600}{5} = ₹320 **The cost price of the article is ₹320.**

Answer

A. ₹315

Answer

C. ₹325

Answer

D. ₹330

Quantitative Aptitude - MCQ Practice Questions